Question Number 205657 by mnjuly1970 last updated on 26/Mar/24
Answered by mr W last updated on 26/Mar/24
$${small}\:{square}:\:{a}×{a}=\mathrm{6}×\mathrm{6} \\ $$$${big}\:{square}:\:{b}×{b} \\ $$$${area}\:{of}\:{triangle}: \\ $$$${A}_{\mathrm{1}} +{A}_{\mathrm{2}} −{A}_{\mathrm{3}} \\ $$$$=\frac{{a}^{\mathrm{2}} }{\mathrm{2}}+\frac{\left({a}+{b}\right){b}}{\mathrm{2}}−\frac{\left({a}+{b}\right){b}}{\mathrm{2}}=\frac{{a}^{\mathrm{2}} }{\mathrm{2}}=\frac{\mathrm{6}^{\mathrm{2}} }{\mathrm{2}}=\mathrm{18}\:\checkmark \\ $$
Commented by mr W last updated on 26/Mar/24
Commented by mr W last updated on 26/Mar/24
Commented by mnjuly1970 last updated on 26/Mar/24
$$\:\:\:\:{thanks}\:{alot}\:{sir}\:{W}\:.{grateful} \\ $$