Question-205892

Question Number 205892 by cortano12 last updated on 02/Apr/24

Answered by A5T last updated on 02/Apr/24

Commented by A5T last updated on 02/Apr/24

A C = y t a n (3 α); x = y t a n α; z = \frac{y}{c o s α}; c = y (t a n 3 α - t a n α)

E C = \frac{y}{c o s 3 α}

\frac{s i n (90 + α)}{\frac{y}{c o s α}} = \frac{s i n (2 α)}{8} \Rightarrow \frac{s i n (90 + α) c o s α}{y} = \frac{2 s i n α c o s α}{8}

\Rightarrow \frac{s i n (90 + α)}{y} = \frac{s i n α}{4} \Rightarrow t a n α = \frac{4}{y} = \frac{x}{y} \Rightarrow x = 4

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