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D-4y-2-sin-xy-dxdy-D-x-y-x-0-y-pi-2-0-x-y-0-y-pi-2-




Question Number 205935 by EJJDJX last updated on 03/Apr/24
∫∫_D (4y^2 sin(xy))dxdy  = ???  D:       x=y      x=0       y=(√(π/2))               0≤x≤y       0≤y≤(√(π/2))
D(4y2sin(xy))dxdy=???D:x=yx=0y=π20xy0yπ2
Answered by Berbere last updated on 03/Apr/24
∫_0 ^(√(π/2)) ∫_0 ^y 4y^2 sin(xy)dxdy  =∫_0 ^(√(π/2)) −4y[cos(xy)]_0 ^y dy  =∫_0 ^(√(π/2)) −4y[cos(y^2 )−1)dy  =−2∫_0 ^(√(π/2)) (cos(y^2 )−1)dy^2   =2∫_0 ^(√(π/2)) (sin(y^2 )−y^2 )  =2(1−(π/2))
0π20y4y2sin(xy)dxdy=0π24y[cos(xy)]0ydy=0π24y[cos(y2)1)dy=20π2(cos(y2)1)dy2=20π2(sin(y2)y2)=2(1π2)

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