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Question Number 205919 by Red1ight last updated on 03/Apr/24
write the following recursive function in explicit form  f(1)=1  f(n+1)=(n+1)f(n)+n!
writethefollowingrecursivefunctioninexplicitformf(1)=1f(n+1)=(n+1)f(n)+n!
Answered by Tinku Tara last updated on 03/Apr/24
f(n)=(n)f(n−1)+(n−1)!  f(n)=nf(n−1)+((n!)/n)  =n[(n−1)f(n−2)+(((n−1)!)/((n−1)))]+((n!)/n)  =n(n−1)f(n−2)+((n!)/((n−1)))+((n!)/n)  continue  f(n)=n!+Σ_(i=2) ^n ((n!)/i)
f(n)=(n)f(n1)+(n1)!f(n)=nf(n1)+n!n=n[(n1)f(n2)+(n1)!(n1)]+n!n=n(n1)f(n2)+n!(n1)+n!ncontinuef(n)=n!+ni=2n!i

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