Menu Close

Question-206045




Question Number 206045 by mr W last updated on 05/Apr/24
Commented by mr W last updated on 05/Apr/24
a special case of Q206053
aspecialcaseofQ206053
Answered by HeferH24 last updated on 05/Apr/24
 A+E = F+B   ... (+)   F+D = E+C    (F+E = 21)   A+D = B+C      A+9 + x + D = E+F+C+B    9+x = 21   x = 12
A+E=F+B(+)F+D=E+C(F+E=21)A+D=B+CA+9+x+D=E+F+C+B9+x=21x=12
Commented by HeferH24 last updated on 05/Apr/24
Commented by mr W last updated on 05/Apr/24
��
Answered by A5T last updated on 07/Apr/24
9+[BGE]+x+[HFD]=21+[AGF]+[EHC]..(i)  9+[AGF]+x+[HEC]=21+[BGE]+[HFD]..(ii)  (i)−(ii): [BGE]−[AGF]+[HFD]−[HEC]  =[AGF]−[BGE]+[EHC]−[HFD]  ⇒[BGE]+[HFD]=[AGF]+[HEC] into (i)  ⇒9+x=21⇒x=12
9+[BGE]+x+[HFD]=21+[AGF]+[EHC]..(i)9+[AGF]+x+[HEC]=21+[BGE]+[HFD]..(ii)(i)(ii):[BGE][AGF]+[HFD][HEC]=[AGF][BGE]+[EHC][HFD][BGE]+[HFD]=[AGF]+[HEC]into(i)9+x=21x=12

Leave a Reply

Your email address will not be published. Required fields are marked *