Menu Close

1-1-t-2-t-dt-




Question Number 206248 by MetaLahor1999 last updated on 10/Apr/24
∫(1/( (√((1−t)(2−t)))))dt=...?
1(1t)(2t)dt=?
Answered by TonyCWX08 last updated on 10/Apr/24
∫(1/( (√(t^2 −3t+2))))dt  =∫(1/( (√((t−(3/2))^2 −(1/4)))))dt  let  u = t−(3/2)   du = dx  ∫ (du/( (√(u^2 −(1/4)))))  =ln(∣u+(√(u^2 −(1/4)))∣)+c  =ln(∣t−(3/2)+(√((t−(3/2))^2 −(1/4)))∣)+c  =ln(∣t−(3/2)+(√(t^2 −3t+2))∣)+c
1t23t+2dt=1(t32)214dtletu=t32du=dxduu214=ln(u+u214)+c=ln(t32+(t32)214)+c=ln(t32+t23t+2)+c
Commented by Frix last updated on 10/Apr/24
Yes. But for the less advanced it would be  nice to show the path for  ∫(du/( (√(u^2 ±c))))=ln ∣u+(√(u^2 ±c))∣
Yes.Butforthelessadvanceditwouldbenicetoshowthepathforduu2±c=lnu+u2±c
Commented by TonyCWX08 last updated on 11/Apr/24
If you want, sure.  But it involves some trigonometry substitution.
Ifyouwant,sure.Butitinvolvessometrigonometrysubstitution.

Leave a Reply

Your email address will not be published. Required fields are marked *