1-1-t-2-t-dt- Tinku Tara April 10, 2024 Integration 0 Comments FacebookTweetPin Question Number 206248 by MetaLahor1999 last updated on 10/Apr/24 ∫1(1−t)(2−t)dt=…? Answered by TonyCWX08 last updated on 10/Apr/24 ∫1t2−3t+2dt=∫1(t−32)2−14dtletu=t−32du=dx∫duu2−14=ln(∣u+u2−14∣)+c=ln(∣t−32+(t−32)2−14∣)+c=ln(∣t−32+t2−3t+2∣)+c Commented by Frix last updated on 10/Apr/24 Yes.Butforthelessadvanceditwouldbenicetoshowthepathfor∫duu2±c=ln∣u+u2±c∣ Commented by TonyCWX08 last updated on 11/Apr/24 Ifyouwant,sure.Butitinvolvessometrigonometrysubstitution. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: 3x-2-12x-5-x-2-4x-1-5-0-Next Next post: f-x-log-2-x-2-x-4-f-1-13-4-3- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.