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Question-206338




Question Number 206338 by mnjuly1970 last updated on 12/Apr/24
Answered by Sorena last updated on 12/Apr/24
[x]−[x^2 ]≥0 → [x]≥[x^2 ] → x∈[0,(√2))
$$\left[{x}\right]−\left[{x}^{\mathrm{2}} \right]\geqslant\mathrm{0}\:\rightarrow\:\left[{x}\right]\geqslant\left[{x}^{\mathrm{2}} \right]\:\rightarrow\:{x}\in\left[\mathrm{0},\sqrt{\mathrm{2}}\right) \\ $$

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