Menu Close

If-4-p-5-Find-2-3p-




Question Number 206473 by hardmath last updated on 15/Apr/24
If   4^p  = 5  Find:   2^(3p)  = ?
If4p=5Find:23p=?
Answered by A5T last updated on 15/Apr/24
2^(2p) =5⇒2^(3p) =(√(125))    p=((log_2 5)/2)⇒2^(3p) =2^(log_2 (5^(3/2) )) =5^(3/2) =(√(125))=5(√5)
22p=523p=125p=log25223p=2log2(532)=532=125=55
Commented by hardmath last updated on 15/Apr/24
thank you very much professor
thankyouverymuchprofessor
Answered by Rasheed.Sindhi last updated on 15/Apr/24
2^(3p) =(2^2 )^((3p)/2) =(4^p )^(3/2) =5^(3/2) =(√(125)) =5(√5)
23p=(22)3p2=(4p)3/2=53/2=125=55
Answered by BaliramKumar last updated on 16/Apr/24
2^(2p)  = 5          ⇒  2 = 5^(1/(2p))   2^(3p)  = (5^(1/(2p)) )^(3p)  = 5^((3p)/(2p))  = 5^(3/2)  = 5(√5)
22p=52=512p23p=(512p)3p=53p2p=532=55
Answered by Skabetix last updated on 16/Apr/24
(2^2 )^p =5  ⇔ 2^(2p) =5  ⇔(2^(2p) )^(3/2) =5^(3/2)   ⇔2^(2p×(3/2)) =5^(3/2)   ⇔2^(3p) =5^(3/2) =5(√5)
(22)p=522p=5(22p)32=53222p×32=53223p=532=55

Leave a Reply

Your email address will not be published. Required fields are marked *