Question-206452

Question Number 206452 by langatfredrick last updated on 15/Apr/24

Answered by A5T last updated on 15/Apr/24

I f r e m a i n d e r m e a n s ∣ x - y ∣, t h e n :

\frac{t_{x}}{x} = x; \frac{t_{y}}{y} = y \Rightarrow t_{∣ x - y ∣} =∣ t_{x} - t_{y} ∣=∣ x^{2} - y^{2} ∣

\Rightarrow \frac{t_{∣ x - y ∣}}{∣ x - y ∣} =∣ x + y ∣= x + y

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