Question-206557 Tinku Tara April 18, 2024 Integration 0 Comments FacebookTweetPin Question Number 206557 by luciferit last updated on 18/Apr/24 Answered by Frix last updated on 18/Apr/24 Withoutsubstitution:∫3+2sin2xcos2xdx=∫(5cos2x−2)dx==5tanx−2x+C Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: 0-e-x-2-x-2-1-2-2-dx-Next Next post: Evaluate-0-1-ln-1-x-2-1-x-d-x- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.