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Question-206614




Question Number 206614 by cortano21 last updated on 20/Apr/24
Commented by BaliramKumar last updated on 20/Apr/24
Q. 188151
$$\mathrm{Q}.\:\mathrm{188151} \\ $$
Answered by BaliramKumar last updated on 20/Apr/24
2022((2022)/(2023)) = ((2022×2023+2022)/(2023)) = (((2023+1)2022)/(2023))          ⇒ ((2024×2022)/(2023)) = ((2023^2 −1)/(2023))
$$\mathrm{2022}\frac{\mathrm{2022}}{\mathrm{2023}}\:=\:\frac{\mathrm{2022}×\mathrm{2023}+\mathrm{2022}}{\mathrm{2023}}\:=\:\frac{\left(\mathrm{2023}+\mathrm{1}\right)\mathrm{2022}}{\mathrm{2023}}\:\:\:\:\:\:\:\: \\ $$$$\Rightarrow\:\frac{\mathrm{2024}×\mathrm{2022}}{\mathrm{2023}}\:=\:\frac{\mathrm{2023}^{\mathrm{2}} −\mathrm{1}}{\mathrm{2023}} \\ $$

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