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Let-f-x-x-x-10-and-let-A-be-the-region-enclosed-within-the-following-points-2-7-8-7-2-4-8-4-what-is-the-average-arc-length-of-a-f-x-inside-A-a-R-




Question Number 206645 by Red1ight last updated on 21/Apr/24
Let f(x)=x(x−10)  and let A be the region enclosed within  the following points  (2,7),(8,7),(2,4),(8,4)  what is the average arc length of a∙f(x)  inside A,a∈R^−
Letf(x)=x(x10)andletAbetheregionenclosedwithinthefollowingpoints(2,7),(8,7),(2,4),(8,4)whatistheaveragearclengthofaf(x)insideA,aR
Commented by mr W last updated on 21/Apr/24
what′s your definition for “average  arc length”?
whatsyourdefinitionforaveragearclength?
Commented by Red1ight last updated on 22/Apr/24
Sum of lengths for all possible arcs  that can be drawn  within that region  devided by the range of a  avg=((ΣL_i )/(a_(max) −a_(min) ))  where L_i  is a length of an arc when a=a_i   where it is also within the region  where a_(min) ≤a_i ≤a_(max)
Sumoflengthsforallpossiblearcsthatcanbedrawnwithinthatregiondevidedbytherangeofaavg=ΣLiamaxaminwhereLiisalengthofanarcwhena=aiwhereitisalsowithintheregionwhereaminaiamax
Commented by Red1ight last updated on 22/Apr/24
  for example the green parabola represents a=-0.1 which from yhe plot is it not within the region     while the red and blue (a=-0.2,a=-0.3) parabola are within. so their arc length is included in the summation
for example the green parabola represents a=-0.1 which from yhe plot is it not within the region

while the red and blue (a=-0.2,a=-0.3) parabola are within. so their arc length is included in the summation

Commented by Red1ight last updated on 22/Apr/24
Commented by mr W last updated on 22/Apr/24
i asked this because you gave a∈R^− ,  which means a_(min) =−∞, a_(max) =0.
iaskedthisbecauseyougaveaR,whichmeansamin=,amax=0.
Answered by Frix last updated on 22/Apr/24
y=ax(x−10)  Arc length α≤x≤β: ∫_α ^β (√(1+(y′)^2 ))dx  1. −(7/(16))≤a≤−(7/(25))       2 interections with y=7: x=5±(√((25a+7)/a))       ((400)/(63))∫_(−(7/(16))) ^(−(7/(25))) (2∫_2 ^(5−(√((25a+7)/a))) (√(1+(y′)^2 ))dx)da≈3.05122  2. −(7/(25))≤a≤−(1/4)       ((100)/3)∫_(−(7/(25))) ^(−(1/4)) (2∫_2 ^5 (√(1+(y′)^2 ))dx)da≈7.98232  3. −(1/4)≤a≤−(4/(25))       2 intersections with y=4: x=5±(√((25a+4)/a))       ((100)/9)∫_(−(1/4)) ^(−(4/(25))) (2∫_(5−(√((25a+4)/a))) ^5 (√(1+(y′)^2 ))dx)da≈5.06862  Sum of these ≈ 16.1022
y=ax(x10)Arclengthαxβ:βα1+(y)2dx1.716a7252interectionswithy=7:x=5±25a+7a40063725716(2525a+7a21+(y)2dx)da3.051222.725a14100314725(2521+(y)2dx)da7.982323.14a4252intersectionswithy=4:x=5±25a+4a100942514(25525a+4a1+(y)2dx)da5.06862Sumofthese16.1022

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