Question Number 206636 by mathzup last updated on 21/Apr/24
$${resoudre}\:{dans}\:{N}^{\mathrm{2}} \:\:{l}\:{equation} \\ $$$$\mathrm{2}{x}^{\mathrm{2}} +\mathrm{3}{y}^{\mathrm{2}} =\mathrm{35} \\ $$
Commented by A5T last updated on 21/Apr/24
$$\left({x},{y}\right)=\left(\mathrm{4},\mathrm{1}\right) \\ $$$${x}\in\mathbb{N}\Rightarrow\mathrm{2}\leqslant\mathrm{2}{x}^{\mathrm{2}} \leqslant\mathrm{35}\Rightarrow\:\mathrm{1}\leqslant{x}\leqslant\mathrm{4},\:{then}\:{check}. \\ $$