Question Number 206675 by BaliramKumar last updated on 22/Apr/24
$$ \\ $$There are three positive integers a, b, and c such that
their average is 35 and a ≤ b ≤ c. If the median is
(a + 18), then find the minimum possible value of c.
(1) 41. (2) 42. (3) 39. (4) 40
their average is 35 and a ≤ b ≤ c. If the median is
(a + 18), then find the minimum possible value of c.
(1) 41. (2) 42. (3) 39. (4) 40
Answered by mr W last updated on 22/Apr/24
$${a}>\mathrm{0} \\ $$$${a}+{b}+{c}=\mathrm{3}×\mathrm{35}=\mathrm{105} \\ $$$${b}={a}+\mathrm{18}\leqslant{c} \\ $$$${c}=\mathrm{105}−{a}−{a}−\mathrm{18}=\mathrm{87}−\mathrm{2}{a}\geqslant{a}+\mathrm{18} \\ $$$$\Rightarrow{a}\leqslant\mathrm{23} \\ $$$${c}=\mathrm{87}−\mathrm{2}{a}\geqslant\mathrm{87}−\mathrm{2}×\mathrm{23}=\mathrm{41}\:\checkmark \\ $$$$\Rightarrow{answer}\:\left(\mathrm{1}\right) \\ $$
Commented by BaliramKumar last updated on 22/Apr/24
$$\mathrm{thanks} \\ $$