Find-the-missing-number-determinant-72-24-6-96-16-12-108-18-A-12-B-16-C-18-D-20-Please-help-

Question Number 206709 by Nimnim111118 last updated on 23/Apr/24

Find the missing number

\begin{array}{ccc} 72 & 24 & 6 \\ 96 & 16 & 12 \\ 108 & ? & 18 \end{array}

A . 12 B . 16 C . 18 D . 20

Please help \dots

Commented by Frix last updated on 24/Apr/24

E . 42

The answer is a l w a y s 42 .

Commented by Ghisom last updated on 24/Apr/24

how? ��

Commented by A5T last updated on 24/Apr/24

I g u e s s {h e}^{'} s j u s t j o k i n g a n d t r y i n g t o p o i n t

o u t t h e s e s o r t o f q u e s t i o n s a r e n o t a c t u a l l y

“ {o b j e c t i v e}^{″} .

Commented by jihamine2301 last updated on 03/May/24

12 c a u s e f i r s t l i n e \frac{72}{6} = 12 \times 2 = 24

\frac{96}{12} = 8 \times 2 = 16

\frac{108}{18} = 6 \times 2 = 12

Answered by BaliramKumar last updated on 23/Apr/24

72 = \frac{24}{2} \times 6

96 = \frac{16}{2} \times 12

108 = \frac{x}{2} \times 18 \Rightarrow 108 = 9 x \Rightarrow x = 12

Commented by Nimnim111118 last updated on 23/Apr/24

Thank you Sir

Answered by Ghisom last updated on 24/Apr/24

72 + 24 + 6 = 102

96 + 16 + 12 = 102 + 22

108 + x + 18 = 102 + 22 + 22 \Rightarrow x = 20

Answered by Frix last updated on 24/Apr/24

l = number of line, λ := 9 - \frac{l (l + 5)}{6}

l = 1 \Rightarrow λ = 8; 72 - 24 = 6 λ = 48

l = 2 \Rightarrow λ = \frac{20}{3}; 96 - 16 = 12 λ = 80

l = 3 \Rightarrow λ = 5; 108 - x = 18 λ = 90 \Rightarrow x = 18 ★

\dots wait, now {where}^{'} s 42 ? ? ?

72 + 24 = 96 + 12 = 108 + 6 = 114

6 + 6 = 12 + 6 = 18 + 6 = 24

\Rightarrow

Line 4 : ∣ 114 ∣ ? ∣ 24 ∣

l = 4 \Rightarrow λ = 3; 114 - y = 24 λ = 72 \Rightarrow y = 42

Ha! I knew it!

Commented by Ghisom last updated on 24/Apr/24

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