Menu Close

Question-206729




Question Number 206729 by mr W last updated on 23/Apr/24
Answered by A5T last updated on 23/Apr/24
((sin84)/(AD))=((sin54)/(AC))⇒AD=((ACsin84)/(sin54))...(i)  ((sin(?))/(AD))=((sin(54−?))/(BD=AC))⇒AD=((ACsin(?))/(sin(54−?)))...(ii)  (i)&(ii)⇒((sin84)/(sin54))=((sin(?))/(sin(54−?)))⇒?=30°
sin84AD=sin54ACAD=ACsin84sin54(i)sin(?)AD=sin(54?)BD=ACAD=ACsin(?)sin(54?)(ii)(i)&(ii)sin84sin54=sin(?)sin(54?)?=30°
Commented by mr W last updated on 23/Apr/24
��

Leave a Reply

Your email address will not be published. Required fields are marked *