Question Number 206737 by mr W last updated on 23/Apr/24

Commented by A5T last updated on 23/Apr/24

Commented by mr W last updated on 23/Apr/24

Commented by A5T last updated on 23/Apr/24

Commented by mr W last updated on 23/Apr/24

Answered by A5T last updated on 23/Apr/24

Commented by A5T last updated on 23/Apr/24
![((DG)/(AG))=((10)/(16))=(5/8); DG=5x;AG=8x ((CG)/(BG))=(5/8); CG=5y;BG=8y 25x^2 =100+25y^2 ⇒x^2 −y^2 =4⇒x=(√(4+y^2 )) EC=8x−12−5y=8(√(4+y^2 ))−5y−12 AC=8(√(4+y^2 ))−5y; BD=8y−5(√(4+y^2 )) BF=8y−5(√(4+y^2 ))−6 [ABDC]=((AB×BD+AC×CD)/2)=39y [BFA]+[DEC]=((AB×BF+EC×DC)/2)=39y−108 ⇒[FAED]=39y−(39y−108)=108](https://www.tinkutara.com/question/Q206744.png)
Commented by mr W last updated on 23/Apr/24
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Answered by mr W last updated on 23/Apr/24

Commented by mr W last updated on 23/Apr/24
