Question Number 206750 by mr W last updated on 23/Apr/24
Answered by HeferH24 last updated on 23/Apr/24
$$\:{By}\:{similar}\:{triangles}: \\ $$$$\:\frac{{d}}{{c}}\:=\:\frac{{x}}{{b}}\:;\:\:\frac{{d}}{{c}}\:=\:\frac{{a}}{{x}}\: \\ $$$$\:\frac{{a}}{{x}}\:=\:\frac{{x}}{{b}}\:\Leftrightarrow\:{x}^{\mathrm{2}} \:=\:{ab}\:\Leftrightarrow\:{x}=\sqrt{{ab}} \\ $$
Commented by HeferH24 last updated on 23/Apr/24
Commented by mr W last updated on 24/Apr/24
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