Question-206956

Question Number 206956 by mr W last updated on 01/May/24

Commented by mr W last updated on 01/May/24

f i n d t h e r a d i u s o f c i r c l e .

Answered by Frix last updated on 01/May/24

3 points given

(\begin{matrix} 0 \\ 0 \end{matrix}) (\begin{matrix} 0 \\ 6 \end{matrix}) (\begin{matrix} 12 \\ 12 \end{matrix})

\Rightarrow Triangle with sides

6 6 \sqrt{5} 12 \sqrt{2}

\Rightarrow R = 3 \sqrt{10}

Commented by mr W last updated on 01/May/24

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Answered by mr W last updated on 01/May/24

Commented by mr W last updated on 01/May/24

B C = \sqrt{{(6 + 4 + 2)}^{2} + {(4 + 2)}^{2}} = 6 \sqrt{5}

R = \frac{B C}{2 \sin A} = \frac{6 \sqrt{5}}{2 \times \frac{\sqrt{2}}{2}} = 3 \sqrt{10}

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