2-x-6-2-x-10-2-x-2-4-2-x-1-2-x-2-Find-x-

Question Number 207218 by hardmath last updated on 09/May/24

2^{x} + \frac{6 \cdot 2^{x} - 10}{2^{x} - 2} = 4 \cdot 2^{x} + \frac{1}{2^{x} - 2}

Find : x = ?

Answered by Frix last updated on 10/May/24

Transform to

{(2^{x})}^{2} - 4 \times 2^{x} + \frac{11}{3} = 0

2^{x} = 2 \pm \frac{\sqrt{3}}{3}

x = \frac{\ln (6 \pm \sqrt{3}) - \ln 3}{\ln 2}

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