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If-xy-1-3-xz-3-8-and-yz-1-2-For-x-y-and-z-compare-




Question Number 207197 by hardmath last updated on 09/May/24
If   xy = (1/3)   ,   xz = (3/8)   and   yz = (1/2)  For   x , y and z   compare.
Ifxy=13,xz=38andyz=12Forx,yandzcompare.
Answered by A5T last updated on 09/May/24
x=(1/(3y));z=(1/(2y))  xz=(3/8)⇒(1/(6y^2 ))=(3/8)⇒y^2 =(4/9)⇒y=+_− (2/3)  ⇒x=+_− (1/2);z=+_− (3/4)
x=13y;z=12yxz=3816y2=38y2=49y=+23x=+12;z=+34
Answered by mr W last updated on 09/May/24
(i)×(ii)×(iii):  (xyz)^2 =(1/3)×(3/8)×(1/2)=(1/(16))  ⇒xyz=±(1/4)      ...(iv)  (iv)/(i):  z=±(3/4)  (iv)/(ii):  y=±(2/3)  (iv)/(iii):  x=±(1/2)
(i)×(ii)×(iii):(xyz)2=13×38×12=116xyz=±14(iv)(iv)/(i):z=±34(iv)/(ii):y=±23(iv)/(iii):x=±12
Commented by hardmath last updated on 09/May/24
dear professor, x,y,z>0
dearprofessor,x,y,z>0
Commented by mr W last updated on 09/May/24
but it was not said that x, y, z >0.
butitwasnotsaidthatx,y,z>0.
Commented by mr W last updated on 09/May/24
if x,y,z>0 then x<y<z
ifx,y,z>0thenx<y<z
Commented by hardmath last updated on 09/May/24
thank you dear professor
thankyoudearprofessor

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