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a-b-c-d-a-3-b-3-625-c-3-d-3-1-Find-a-b-c-d-




Question Number 207394 by hardmath last updated on 13/May/24
(a/b)  =  (c/d)  a^3  − b^3  = 625  c^3  − d^3  = 1  Find:   a,b,c,d = ?
ab=cda3b3=625c3d3=1Find:a,b,c,d=?
Answered by mr W last updated on 13/May/24
(a/b)=(c/d)=k, say  a=kb, c=kd with k≠1  b^3 (k^3 −1)=625 ⇒b=(((625)/(k^3 −1)))^(1/3)  ⇒a=k(((625)/(k^3 −1)))^(1/3)   d^3 (k^3 −1)=1 ⇒d=(1/( ((k^3 −1))^(1/3) )) ⇒c=(k/( ((k^3 −1))^(1/3) ))  3 equations for 4 variables, so  there is no unique solution.
ab=cd=k,saya=kb,c=kdwithk1b3(k31)=625b=625k313a=k625k313d3(k31)=1d=1k313c=kk3133equationsfor4variables,sothereisnouniquesolution.

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