a-b-c-d-a-3-b-3-625-c-3-d-3-1-Find-a-b-c-d- Tinku Tara May 13, 2024 Algebra 0 Comments FacebookTweetPin Question Number 207394 by hardmath last updated on 13/May/24 ab=cda3−b3=625c3−d3=1Find:a,b,c,d=? Answered by mr W last updated on 13/May/24 ab=cd=k,saya=kb,c=kdwithk≠1b3(k3−1)=625⇒b=625k3−13⇒a=k625k3−13d3(k3−1)=1⇒d=1k3−13⇒c=kk3−133equationsfor4variables,sothereisnouniquesolution. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Geometric-series-b-4-b-7-b-10-b-1-b-3-b-5-2-12-find-b-5-b-2-Next Next post: f-x-2f-1-x-3x-f-x- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.