Menu Close

Question-207407




Question Number 207407 by hardmath last updated on 13/May/24
Commented by Frix last updated on 13/May/24
2. ...=2(√3)cos 10°
$$\mathrm{2}.\:…=\mathrm{2}\sqrt{\mathrm{3}}\mathrm{cos}\:\mathrm{10}° \\ $$
Commented by Frix last updated on 14/May/24
For the 1^(st)  one I found nothing but this:  it is one solution of  x^3 −12x^2 +27x−17=0  which gives nasty solutions but I found a  possibility to express them  The 2^(nd)  one is one solution of  x^3 −9x−9=0  which gives nice solutions  I′ll post these tomorrow, time to sleep here  right now...
$$\mathrm{For}\:\mathrm{the}\:\mathrm{1}^{\mathrm{st}} \:\mathrm{one}\:\mathrm{I}\:\mathrm{found}\:\mathrm{nothing}\:\mathrm{but}\:\mathrm{this}: \\ $$$$\mathrm{it}\:\mathrm{is}\:\mathrm{one}\:\mathrm{solution}\:\mathrm{of} \\ $$$${x}^{\mathrm{3}} −\mathrm{12}{x}^{\mathrm{2}} +\mathrm{27}{x}−\mathrm{17}=\mathrm{0} \\ $$$$\mathrm{which}\:\mathrm{gives}\:\mathrm{nasty}\:\mathrm{solutions}\:\mathrm{but}\:\mathrm{I}\:\mathrm{found}\:\mathrm{a} \\ $$$$\mathrm{possibility}\:\mathrm{to}\:\mathrm{express}\:\mathrm{them} \\ $$$$\mathrm{The}\:\mathrm{2}^{\mathrm{nd}} \:\mathrm{one}\:\mathrm{is}\:\mathrm{one}\:\mathrm{solution}\:\mathrm{of} \\ $$$${x}^{\mathrm{3}} −\mathrm{9}{x}−\mathrm{9}=\mathrm{0} \\ $$$$\mathrm{which}\:\mathrm{gives}\:\mathrm{nice}\:\mathrm{solutions} \\ $$$$\mathrm{I}'\mathrm{ll}\:\mathrm{post}\:\mathrm{these}\:\mathrm{tomorrow},\:\mathrm{time}\:\mathrm{to}\:\mathrm{sleep}\:\mathrm{here} \\ $$$$\mathrm{right}\:\mathrm{now}… \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *