Question Number 207463 by hardmath last updated on 16/May/24
$$\mathrm{1}\:−\:\mathrm{sin}^{\mathrm{2}} \:\mathrm{x}\:=\:\sqrt{\mathrm{2}}\:\:\:\:\:\mathrm{find}:\:\:\boldsymbol{\mathrm{x}}\:=\:? \\ $$
Answered by Frix last updated on 16/May/24
$$\mathrm{cos}^{\mathrm{2}} \:{x}\:=\sqrt{\mathrm{2}}>\mathrm{1}\:\Rightarrow\:\mathrm{no}\:\mathrm{solution}\:\mathrm{for}\:{x}\in\mathbb{R} \\ $$