Question Number 207462 by hardmath last updated on 16/May/24
$$\mathrm{4}\:\mathrm{sin}\:\frac{\boldsymbol{\mathrm{x}}}{\mathrm{2}}\:=\:\mathrm{1}\:\:\:\:\:\mathrm{find}:\:\:\boldsymbol{\mathrm{x}}\:=\:? \\ $$
Commented by Frix last updated on 16/May/24
$${x}=\mathrm{4}{n}\pi+\mathrm{2sin}^{−\mathrm{1}} \:\frac{\mathrm{1}}{\mathrm{4}}\:\vee{x}=\mathrm{2}\left(\mathrm{2}{n}+\mathrm{1}\right)\pi−\mathrm{2sin}^{−\mathrm{1}} \:\frac{\mathrm{1}}{\mathrm{4}} \\ $$