Question Number 207458 by 073 last updated on 16/May/24
Commented by 073 last updated on 16/May/24
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Commented by mr W last updated on 16/May/24
$$\mathrm{B}\left({x},\:{y}\right)=\frac{\Gamma\left({x}\right)\Gamma\left({y}\right)}{\Gamma\left({x}+{y}\right)}\overset{!} {=}\Gamma\left({x}\right) \\ $$$$\Rightarrow\frac{\Gamma\left({y}\right)}{\Gamma\left({x}+{y}\right)}=\mathrm{1} \\ $$$$\Rightarrow\Gamma\left({x}+{y}\right)=\Gamma\left({y}\right)\:\Rightarrow{no}\:{solution}\:{for}\:{y} \\ $$