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4-cos-50-1-sin-20-




Question Number 207562 by hardmath last updated on 18/May/24
4 cos 50° − (1/(sin 20°))  =  ?
$$\mathrm{4}\:\mathrm{cos}\:\mathrm{50}°\:−\:\frac{\mathrm{1}}{\mathrm{sin}\:\mathrm{20}°}\:\:=\:\:? \\ $$
Commented by Frix last updated on 18/May/24
−2tan 10°
$$−\mathrm{2tan}\:\mathrm{10}° \\ $$

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