Menu Close

x-2-lg-x-3-0-




Question Number 207558 by hardmath last updated on 18/May/24
(x − 2) lg (x/3)  ≥  0
$$\left(\mathrm{x}\:−\:\mathrm{2}\right)\:\mathrm{lg}\:\frac{\mathrm{x}}{\mathrm{3}}\:\:\geqslant\:\:\mathrm{0} \\ $$
Answered by mr W last updated on 19/May/24
x−2≥0 ∧ (x/3)≥1 ⇒x≥3 ✓  or  x−2≤0 ∧ 0<(x/3)≤1 ⇒0<x≤2 ✓
$${x}−\mathrm{2}\geqslant\mathrm{0}\:\wedge\:\frac{{x}}{\mathrm{3}}\geqslant\mathrm{1}\:\Rightarrow{x}\geqslant\mathrm{3}\:\checkmark \\ $$$${or} \\ $$$${x}−\mathrm{2}\leqslant\mathrm{0}\:\wedge\:\mathrm{0}<\frac{{x}}{\mathrm{3}}\leqslant\mathrm{1}\:\Rightarrow\mathrm{0}<{x}\leqslant\mathrm{2}\:\checkmark \\ $$
Commented by hardmath last updated on 19/May/24
thank you professor
$$\mathrm{thank}\:\mathrm{you}\:\mathrm{professor} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *