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Given-x-1-x-3-x-2023-25-x-2-x-4-x-2022-x-1-2-x-3-2-x-2023-2-125-x-2-2-x-4-2-x-2022-2-2-x-i-1-i-1-2-3-2023-x-i-integer-numbe

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Question Number 207663 by efronzo1 last updated on 24/May/24
Given x_1 +x_3 +...+x_(2023) = 25−(x_2 +x_4 +...+x_(2022) ) x_1 ^(2 ) + x_3 ^2 +...+x_(2023) ^2 = 125−(x_2 ^2 +x_4 ^2 +...+x_(2022) ^2 ) −2≤x_i ≤1 , i=1,2,3,...,2023 x_i integer number Find minimum value of x_1 ^3 +x_2 ^3 +x_3 ^3 +x_4 ^3 +...+x_(2023) ^3 □−100 □−71 □−50 □−16
Givenx1+x3+…+x2023=25−(x2+x4+…+x2022)x12+x32+…+x20232=125−(x22+x42+…+x20222)−2⩽xi⩽1,i=1,2,3,…,2023xiintegernumberFindminimumvalueofx13+x23+x33+x43+…+x20233◻−100◻−71◻−50◻−16

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