Question Number 207764 by mr W last updated on 25/May/24
Answered by som(math1967) last updated on 25/May/24
$$\:{R}^{\mathrm{2}} +\mathrm{4}^{\mathrm{2}} =\mathrm{2}\left(\mathrm{2}^{\mathrm{2}} +{R}^{\mathrm{2}} \right) \\ $$$$\Rightarrow{R}^{\mathrm{2}} =\mathrm{16}−\mathrm{8} \\ $$$$\:{R}=\mathrm{2}\sqrt{\mathrm{2}}\:{unit} \\ $$
Commented by mr W last updated on 25/May/24
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Answered by mr W last updated on 25/May/24
Commented by mr W last updated on 25/May/24
$$\frac{\frac{{R}}{\mathrm{2}}}{\mathrm{2}}=\frac{\mathrm{2}}{{R}} \\ $$$${R}^{\mathrm{2}} =\mathrm{8} \\ $$$$\Rightarrow{R}=\mathrm{2}\sqrt{\mathrm{2}} \\ $$
Commented by Tawa11 last updated on 21/Jun/24
$$\mathrm{weldone}\:\mathrm{sir} \\ $$
Answered by cherokeesay last updated on 25/May/24
Commented by mr W last updated on 25/May/24
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