Question Number 207910 by Ismoiljon_008 last updated on 30/May/24
Answered by A5T last updated on 30/May/24
Commented by A5T last updated on 30/May/24
$${AB}=\sqrt{\left(\mathrm{2}+\mathrm{3}\right)^{\mathrm{2}} −\mathrm{1}^{\mathrm{2}} }+\sqrt{\left(\mathrm{1}.\mathrm{5}+\mathrm{2}\right)^{\mathrm{2}} −\left(\mathrm{2}.\mathrm{5}\right)^{\mathrm{2}} } \\ $$$$=\sqrt{\mathrm{24}}+\sqrt{\mathrm{6}}=\mathrm{3}\sqrt{\mathrm{6}} \\ $$