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Find-2-log-5-sin-pi-7-log-sin-7-5-




Question Number 208037 by hardmath last updated on 02/Jun/24
Find:   2 log_(√5)   sin (π/7) ∙ log_(√(sin (𝛑/7)))   5  =  ?
Find:2log5sinπ7logsinπ75=?
Answered by mr W last updated on 02/Jun/24
=2×((log (sin (π/7)))/((log 5)/2))×((log 5)/((log (sin (π/7)))/2))  =8×((log (sin (π/7)))/(log 5))×((log 5)/(log (sin (π/2))))  =8
=2×log(sinπ7)log52×log5log(sinπ7)2=8×log(sinπ7)log5×log5log(sinπ2)=8
Commented by hardmath last updated on 02/Jun/24
thank you dear professor
thankyoudearprofessor

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