Question-208034

Question Number 208034 by ali009 last updated on 02/Jun/24

Commented by ali009 last updated on 02/Jun/24

h o w t h a t c a n b e p r o v e d ?

Answered by Frix last updated on 02/Jun/24

s^{2} + \frac{s}{2} + 2 = {(s + \frac{1}{4})}^{2} + \frac{31}{16} = {(s + \frac{1}{4})}^{2} + {(\frac{\sqrt{31}}{4})}^{2}

\frac{\sqrt{31}}{4} \neq 1.39

{(s + . 25)}^{2} + 1 . 39^{2} = s^{2} + . 5 s + 1.9946

1.9946 \neq 2

So there is no proof .

Commented by ali009 last updated on 02/Jun/24

i t h i n k {i t}^{'} s

\sqrt{2 - 0.0625} ≃ 1.39

b e c a u s e

{(s + 0.25)}^{2} + {(\sqrt{2 - 0.0625})}^{2} = s^{2} + \frac{s}{2} + 2

Commented by Frix last updated on 03/Jun/24

Mathematical proofs are precise . You can

round numbers but you cannot prove that

2 = 1.9946 or \frac{\sqrt{31}}{4} = 1.39

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