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Question-208049




Question Number 208049 by mr W last updated on 03/Jun/24
Commented by Frix last updated on 03/Jun/24
a=1∧b=3  r=a+b−(√(a^2 +b^2 ))=4−(√(10))
a=1b=3r=a+ba2+b2=410
Answered by mr W last updated on 03/Jun/24
Commented by mr W last updated on 03/Jun/24
AB=c=(√(a^2 +b^2 ))  R=(c/2)=((√(a^2 +b^2 ))/2)  (r−(a/2))^2 +(r−(b/2))^2 =(R−r)^2     r−(a+b−2R)=0  ⇒r=a+b−(√(a^2 +b^2 ))
AB=c=a2+b2R=c2=a2+b22(ra2)2+(rb2)2=(Rr)2r(a+b2R)=0r=a+ba2+b2
Commented by Tawa11 last updated on 21/Jun/24
weldone sir
weldonesir

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