Question-208242 Tinku Tara June 8, 2024 Coordinate Geometry 0 Comments FacebookTweetPin Question Number 208242 by alcohol last updated on 08/Jun/24 Commented by alcohol last updated on 08/Jun/24 pleasehelpmetranslateandsolve Answered by mr W last updated on 09/Jun/24 ∫abf(x)dx=∑n−1k=0∫x2kx2(k+1)f(x)dx≈∑n−1k=0x2(k+1)−x2k6[y2k+4y2k+1+y2(k+1)]≈b−a6n∑n−1k=0[y2k+4y2k+1+y2(k+1)]≈b−a6n[2(y0+y2+y4+…+y2n)+4(y1+y3+y5+…+y2n−1)−y0−y2n]≈b−a6n[y0+y2n+2(y2+y4+…+y2n−2)+4(y1+y3+y5+…+y2n−1)]ln2=∫12dxx≈2−16×2[11+12+2(46)+4(45+47)]≈0.69325(withn=2)or≈2−16×3[11+12+2(68+610)+4(67+69+611)]≈0.69317(withn=3) Commented by mr W last updated on 09/Jun/24 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: 1-2-2-2-3-2-5-2-8-2-13-2-21-2-Next Next post: Solve-for-p-q-r-p-q-r-p-2-q-2-r-2-pq-r- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.