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Question-208259




Question Number 208259 by hardmath last updated on 09/Jun/24
Answered by cherokeesay last updated on 09/Jun/24
Answered by mr W last updated on 09/Jun/24
Commented by mr W last updated on 09/Jun/24
CD=CB=((a+b)/2)  ⇒∠CDB=∠CBD=45°  2x+45°=180°  ⇒x=67.5°
CD=CB=a+b2CDB=CBD=45°2x+45°=180°x=67.5°
Commented by Tawa11 last updated on 21/Jun/24
Weldone sir
Weldonesir

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