Question-208322 Tinku Tara June 11, 2024 Logarithms 0 Comments FacebookTweetPin Question Number 208322 by alcohol last updated on 11/Jun/24 Answered by Berbere last updated on 11/Jun/24 ∏n−1k=1(1+1k)k=∏n−1k=1(1+k)kkk=∏n−1k=1(1+k)k+1(k+1).kk=∏n−1k=11(k+1).∏n−1k=1(1+k)k+1kk=1n!.nn=nn−1(n−1)! Answered by MathematicalUser2357 last updated on 13/Jun/24 ✓ Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Resolver-2-u-y-2-x-2-u-xe-4y-Next Next post: lim-x-0-a-x-1-x-log-a- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.