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Question-208421




Question Number 208421 by lepuissantcedricjunior last updated on 15/Jun/24
Commented by Frix last updated on 15/Jun/24
Ψ=2∫_0 ^(π/4) (dx/( (√(tan 2x)))) =^(t=(√(tan 2x)))  2∫_0 ^∞ (dt/(t^4 +1))=(((√2)π)/2)
Ψ=2π40dxtan2x=t=tan2x20dtt4+1=2π2

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