Question Number 208533 by alcohol last updated on 18/Jun/24
$${z}'\:=\:\frac{\mathrm{1}}{\mathrm{2}}\left({z}+\frac{\mathrm{1}}{{z}}\right) \\ $$$${z}\:{and}\:{z}'\:{are}\:{complex}\:{numbers} \\ $$$${show}\:{that}\:{z}\:=\:\mathrm{2}{e}^{{i}\theta} \\ $$$${show}\:{that}\:{M}'\:{describes}\:{a}\:{conic}\:{section} \\ $$
Answered by Berbere last updated on 18/Jun/24
$${what}\:{is}\:{z}\:{complexe} \\ $$$$ \\ $$$${n}\:{plane}?\% \\ $$
Answered by Berbere last updated on 18/Jun/24
$${z}'=\frac{\mathrm{1}}{\mathrm{2}}\left({z}+\frac{\mathrm{1}}{{z}}\right)\:{z}=\mathrm{2}{e}^{{i}\theta} \\ $$$${incomplet}\:{information}\:{we}\:{can}\:{just}\:{say}\:{z}#\mathrm{0} \\ $$$$ \\ $$