Question Number 208581 by Tawa11 last updated on 18/Jun/24
![](https://www.tinkutara.com/question/34152.png)
Commented by mr W last updated on 18/Jun/24
![](https://www.tinkutara.com/question/34155.png)
Commented by Tawa11 last updated on 18/Jun/24
![Thanks sir.](https://www.tinkutara.com/question/Q208589.png)
Answered by A5T last updated on 18/Jun/24
![](https://www.tinkutara.com/question/34153.png)
Commented by A5T last updated on 18/Jun/24
![2^2 −2×2×5cosθ=+2×3×4cosθ ⇒cosθ=(1/(11)) AB=(√(2^2 +5^2 −2×2×5×(1/(11))))=((√(3289))/(11)) ((abc)/(4R))=(1/2)×2×5×((√(120))/(11))⇒R=((√(3289))/( 2(√(120))))](https://www.tinkutara.com/question/Q208583.png)
Commented by Tawa11 last updated on 18/Jun/24
![Thanks sir](https://www.tinkutara.com/question/Q208590.png)