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Question-208591




Question Number 208591 by RoseAli last updated on 18/Jun/24
Answered by A5T last updated on 18/Jun/24
0≤3∣sinx∣≤3; −4≤−4∣cosx∣≤0  ⇒−4≤3∣sinx∣−4∣cosx∣≤3  ⇒y∈[−4,3]
$$\mathrm{0}\leqslant\mathrm{3}\mid{sinx}\mid\leqslant\mathrm{3};\:−\mathrm{4}\leqslant−\mathrm{4}\mid{cosx}\mid\leqslant\mathrm{0} \\ $$$$\Rightarrow−\mathrm{4}\leqslant\mathrm{3}\mid{sinx}\mid−\mathrm{4}\mid{cosx}\mid\leqslant\mathrm{3} \\ $$$$\Rightarrow{y}\in\left[−\mathrm{4},\mathrm{3}\right] \\ $$

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