Question Number 208608 by Tawa11 last updated on 18/Jun/24
![](https://www.tinkutara.com/question/34158.png)
Answered by mr W last updated on 18/Jun/24
![R^2 =((a/2))^2 +((a/2)+b)^2 ⇒R=(√((a^2 /2)+ab+b^2 ))](https://www.tinkutara.com/question/Q208610.png)
$${R}^{\mathrm{2}} =\left(\frac{{a}}{\mathrm{2}}\right)^{\mathrm{2}} +\left(\frac{{a}}{\mathrm{2}}+{b}\right)^{\mathrm{2}} \\ $$$$\Rightarrow{R}=\sqrt{\frac{{a}^{\mathrm{2}} }{\mathrm{2}}+{ab}+{b}^{\mathrm{2}} } \\ $$
Commented by Tawa11 last updated on 18/Jun/24
![Please sir, Show me the connection lines you used. Thanks sir](https://www.tinkutara.com/question/Q208612.png)
$$\mathrm{Please}\:\mathrm{sir}, \\ $$$$\mathrm{Show}\:\mathrm{me}\:\mathrm{the}\:\mathrm{connection}\:\mathrm{lines}\:\mathrm{you}\:\mathrm{used}. \\ $$$$\mathrm{Thanks}\:\mathrm{sir} \\ $$
Commented by mr W last updated on 18/Jun/24
![](https://www.tinkutara.com/question/34159.png)
Commented by Tawa11 last updated on 18/Jun/24
![God bless you sir. I really appreciate](https://www.tinkutara.com/question/Q208614.png)
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$$$\mathrm{I}\:\mathrm{really}\:\mathrm{appreciate} \\ $$
Answered by efronzo1 last updated on 19/Jun/24
![Z⊣2](https://www.tinkutara.com/question/Q208627.png)
$$\:\:\:\underline{\boldsymbol{\mathrm{Z}}}\cancel{\underbrace{\dashv}}\mathrm{2} \\ $$
Commented by Tawa11 last updated on 19/Jun/24
![Thanks sir](https://www.tinkutara.com/question/Q208628.png)
$$\mathrm{Thanks}\:\mathrm{sir} \\ $$