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Question Number 208637 by efronzo1 last updated on 20/Jun/24
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Answered by Berbere last updated on 20/Jun/24
find fractin that one man can compete per day V_m   and women V_w   V_m =(1/(16.24))  V_w =(1/(16.48))  so it just find x ;  14.12.V_m +x(12V_m +12V_w )=1  x.((1/(32))+(1/(64)))=(9/(16))⇒x=4  Total 14+4=18
findfractinthatonemancancompeteperdayVmandwomenVwVm=116.24Vw=116.48soitjustfindx;14.12.Vm+x(12Vm+12Vw)=1x.(132+164)=916x=4Total14+4=18
Commented by efronzo1 last updated on 20/Jun/24
x = 12
x=12
Answered by A5T last updated on 20/Jun/24
In 1 day, the 48 women did (1/(16)) of the job  ⇒1 woman did (1/(16×48)) of the job per day  Similarly, 1 man would do (1/(16×24)) per day  (12×(1/(16×24))×14)+x(((12)/(16×24))+((12)/(16×48)))=1  ⇒x=12
In1day,the48womendid116ofthejob1womandid116×48ofthejobperdaySimilarly,1manwoulddo116×24perday(12×116×24×14)+x(1216×24+1216×48)=1x=12
Answered by MM42 last updated on 20/Jun/24
((16×48)/(16×24))=2⇒m=2w  ⇒number of days to with 12 mens  16×24=12×x⇒x=32  the remaining days of doing work with 12 mens  32−14=18   12 m & 12 w ≡ 18 m  ⇒12×18=18×x⇒x=12 ✓
16×4816×24=2m=2wnumberofdaystowith12mens16×24=12×xx=32theremainingdaysofdoingworkwith12mens3214=1812m&12w18m12×18=18×xx=12

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