Question Number 208647 by hardmath last updated on 20/Jun/24
$$\left(\mathrm{tan}^{\mathrm{2}} \boldsymbol{\mathrm{x}}\:−\:\mathrm{3}\right)\:\centerdot\:\mathrm{sin}\boldsymbol{\mathrm{x}}\:=\:\mathrm{0} \\ $$$$\mathrm{Find}:\:\:\:\boldsymbol{\mathrm{x}}\:=\:? \\ $$
Answered by Frix last updated on 20/Jun/24
$${f}\left({x}\right)×{g}\left({x}\right)=\mathrm{0}\:\Leftrightarrow\:{f}\left({x}\right)=\mathrm{0}\vee{g}\left({x}\right)=\mathrm{0} \\ $$$$\mathrm{sin}\:{x}\:=\mathrm{0}\:\Rightarrow\:{x}={n}\pi \\ $$$$\mathrm{tan}\:{x}\:=\pm\sqrt{\mathrm{3}}\:\Rightarrow\:{x}=\pm\frac{\pi}{\mathrm{3}}+{n}\pi \\ $$