Question Number 208685 by hardmath last updated on 21/Jun/24
$$\mathrm{25}\:\mathrm{tan}\:\mathrm{x}\:=\:\mathrm{3} \\ $$$$\mathrm{x}\:=\:? \\ $$
Answered by Rasheed.Sindhi last updated on 21/Jun/24
$$\mathrm{tan}\:\mathrm{x}=\frac{\mathrm{3}}{\mathrm{25}} \\ $$$$\mathrm{x}=\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{3}}{\mathrm{25}}\right) \\ $$
Commented by mr W last updated on 21/Jun/24
$${x}={k}\pi+\mathrm{tan}^{−\mathrm{1}} \frac{\mathrm{3}}{\mathrm{25}} \\ $$
Commented by Rasheed.Sindhi last updated on 21/Jun/24
$${Of}\:{course}\:\boldsymbol{{sir}}! \\ $$