Question-208772

Question Number 208772 by Jubr last updated on 22/Jun/24

Answered by mr W last updated on 22/Jun/24

Commented by mr W last updated on 22/Jun/24

(r−a)^2 +(r−(a/2))^2 =r^2 4r^2 −12ar+5a^2 =0 a=((2r)/5)=((2×5)/5)=2 area of square =a^2 =2^2 =4

$$\left({r}−{a}\right)^{\mathrm{2}} +\left({r}−\frac{{a}}{\mathrm{2}}\right)^{\mathrm{2}} ={r}^{\mathrm{2}} \\ $$$$\mathrm{4}{r}^{\mathrm{2}} −\mathrm{12}{ar}+\mathrm{5}{a}^{\mathrm{2}} =\mathrm{0} \\ $$$${a}=\frac{\mathrm{2}{r}}{\mathrm{5}}=\frac{\mathrm{2}×\mathrm{5}}{\mathrm{5}}=\mathrm{2} \\ $$$${area}\:{of}\:{square}\:={a}^{\mathrm{2}} =\mathrm{2}^{\mathrm{2}} =\mathrm{4} \\ $$

Commented by Tawa11 last updated on 22/Jun/24

$$\mathrm{Thanks}\:\mathrm{sir}. \\ $$$$\mathrm{I}\:\mathrm{really}\:\mathrm{appreciate}\:\mathrm{sir}. \\ $$

Commented by Wuji last updated on 23/Jun/24

sir, what app do you use for the duagrams?

$$\boldsymbol{\mathrm{sir}},\:\boldsymbol{\mathrm{what}}\:\boldsymbol{\mathrm{app}}\:\boldsymbol{\mathrm{do}}\:\boldsymbol{\mathrm{you}}\:\boldsymbol{\mathrm{use}}\:\boldsymbol{\mathrm{for}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{duagrams}}? \\ $$

Commented by mr W last updated on 23/Jun/24