Question Number 208823 by Ismoiljon_008 last updated on 23/Jun/24

Answered by mr W last updated on 23/Jun/24

Commented by Ismoiljon_008 last updated on 24/Jun/24

Commented by mr W last updated on 24/Jun/24

Commented by mr W last updated on 24/Jun/24

Answered by A5T last updated on 24/Jun/24
![[E]^2 =[(√(a^2 +1))+(√(b^2 +9))+(√(c^2 +16 ))]^2 =a^2 +b^2 +c^2 +1+9+16+2(√(a^2 +1))(√(b^2 +9))+ 2(√(b^2 +9))(√(c^2 +16))+2(√(c^2 +16))(√(a^2 +1)) ≥a^2 +b^2 +c^2 +26+2(ab+1×3)+2(bc+3×4)+ 2(ac+4×1) =(a+b+c)^2 −2ab−2bc−2ca+2ab+2ac+2bc+26 +6+24+8=15^2 +8^2 =17^2 E^2 ≥17^2 ⇒E≥17 Equality when (a,b,c)=(λ,3λ,4λ)⇒8λ=15 ⇒λ=((15)/8)⇒(a,b,c)=(((15)/8),((45)/8),((15)/2))](https://www.tinkutara.com/question/Q208826.png)
Commented by A5T last updated on 24/Jun/24

Commented by Ismoiljon_008 last updated on 24/Jun/24
