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Question-208940




Question Number 208940 by efronzo1 last updated on 28/Jun/24
Answered by kapoorshah last updated on 28/Jun/24
r = OD = (√(10))  BE = (√(15))  BOE ∼ BCA  ((BO)/(BE)) = ((BC)/(AB))  ((√(10))/( (√(15)))) = ((BC)/(2(√(10))))  ⇒ BC = ((20)/( (√(15)))) = 5.164
$${r}\:=\:{OD}\:=\:\sqrt{\mathrm{10}} \\ $$$${BE}\:=\:\sqrt{\mathrm{15}} \\ $$$${BOE}\:\sim\:{BCA} \\ $$$$\frac{{BO}}{{BE}}\:=\:\frac{{BC}}{{AB}} \\ $$$$\frac{\sqrt{\mathrm{10}}}{\:\sqrt{\mathrm{15}}}\:=\:\frac{{BC}}{\mathrm{2}\sqrt{\mathrm{10}}}\:\:\Rightarrow\:{BC}\:=\:\frac{\mathrm{20}}{\:\sqrt{\mathrm{15}}}\:=\:\mathrm{5}.\mathrm{164} \\ $$$$ \\ $$

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