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Question-208999




Question Number 208999 by Spillover last updated on 30/Jun/24
Answered by mr W last updated on 30/Jun/24
Commented by mr W last updated on 30/Jun/24
F=mg−B  m=Vρ_(Iron)  ⇒V=(m/ρ_(Iron) )  B=((Vρ_(Oil) g)/2)=((mρ_(Oil) g)/(2ρ_(Iron) ))  ⇒F=(1−(ρ_(Oil) /(2ρ_(Iron) )))mg          =(1−((0.9)/(2×7.8)))×0.36×10=3.39N
F=mgBm=VρIronV=mρIronB=VρOilg2=mρOilg2ρIronF=(1ρOil2ρIron)mg=(10.92×7.8)×0.36×10=3.39N
Commented by Spillover last updated on 30/Jun/24
nice solution.thank you
nicesolution.thankyou
Answered by Spillover last updated on 30/Jun/24
Answered by Spillover last updated on 30/Jun/24

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