Question-209062 Tinku Tara July 1, 2024 Algebra 0 Comments FacebookTweetPin Question Number 209062 by hardmath last updated on 01/Jul/24 Answered by som(math1967) last updated on 01/Jul/24 xyz=1x,y,z∈N⇒1yz=1⇒x=1yzx=125⇒yz=53⇒y=5⇒z=3zyx=351=2439x+10y−18z=9+10×5−18×3=5 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Compare-8-and-8-Next Next post: Question-209098 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.